April Logic Games class! Feb 23 Written By Van Tran Van will be offering small group classes for students registered for the April LSAT. A different game type will be covered each week. The cost will be $30/class (each class 1.5 hours in length). Please pre-register using the form below: Name * First Name Last Name Email * Are you registered for the April LSAT? (Preference given to April LSAT students, but other students are welcome.) * Yes No Please check all the times you are available (lessons will begin the first week of March and class will have one lesson/week.) * Wednesdays, 1:10pm-2:40pm PST Fridays, 5-6:30pm PST Saturdays, 2-3:30pm PST Saturdays, 5:15-6:45pm PST Please tell us about your level of mastery wih logic games (how many you typically get wrong/section, game types you have trouble with, etc.). Any comments? (General availability if no listed times work, interest in LR/RC classes with Van or another tutor, preference for shorter/longer lessons, concerns about cost? All feedback welcome!) Thank you! Van Tran
April Logic Games class! Feb 23 Written By Van Tran Van will be offering small group classes for students registered for the April LSAT. A different game type will be covered each week. The cost will be $30/class (each class 1.5 hours in length). Please pre-register using the form below: Name * First Name Last Name Email * Are you registered for the April LSAT? (Preference given to April LSAT students, but other students are welcome.) * Yes No Please check all the times you are available (lessons will begin the first week of March and class will have one lesson/week.) * Wednesdays, 1:10pm-2:40pm PST Fridays, 5-6:30pm PST Saturdays, 2-3:30pm PST Saturdays, 5:15-6:45pm PST Please tell us about your level of mastery wih logic games (how many you typically get wrong/section, game types you have trouble with, etc.). Any comments? (General availability if no listed times work, interest in LR/RC classes with Van or another tutor, preference for shorter/longer lessons, concerns about cost? All feedback welcome!) Thank you! Van Tran
